How to print a specific row of a pandas DataFrame?
When you call loc
with a scalar value, you get a pd.Series
. That series will then have one dtype
. If you want to see the row as it is in the dataframe, you'll want to pass an array like indexer to loc
.
Wrap your index value with an additional pair of square brackets
print(df.loc[[159220]])
To print a specific row we have couple of pandas method
loc
- It only get label i.e column name or Featuresiloc
- Here i stands for integer, actually row numberix
- It is a mix of label as well as integer
How to use for specific row
loc
df.loc[row,column]
For first row and all column
df.loc[0,:]
For first row and some specific column
df.loc[0,'column_name']
iloc
For first row and all column
df.iloc[0,:]
For first row and some specific column i.e first three cols
df.iloc[0,0:3]