How to put class="active" to first element in vuejs for loop
The easiest solution is to check every element if index
is equal to 0 and then setting the active
class (or the class you needed). Here is the code of class definition:
:class="{ 'active': index === 0 }"
Here is working example of making Bootstrap Tabs
:
<ul class="nav nav-tabs tab-nav-right" role="tablist">
<li role="presentation" :class="{ 'active': index === 0 }" v-for="(value, index) in some_array" v-bind:key="index">
{{some_array[index]}}
</li>
</ul>
Also, if you have multiple classes you can mix them like this:
:class="['tab-pane fade', (index === 0 ? 'active in' : 'something_else')]"
const TextComponent = {
template: `
<p>{{ text }}</p>
`,
props: ['text'],
};
new Vue({
components: {
TextComponent,
},
template: `
<div>
<text-component
v-for="(item, index) in items"
:class="{ 'active': index === 0 }"
:text="item.text">
</text-component>
</div>
`,
data: {
items: [
{ text: 'Foo' },
{ text: 'Bar' },
{ text: 'Baz' },
],
},
}).$mount('#app');
.active {
background-color: red;
}
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width">
<title></title>
</head>
<body>
<div id="app"></div>
<script src="https://cdnjs.cloudflare.com/ajax/libs/vue/2.0.3/vue.js"></script>
</body>
</html>
Above is a snippet demonstrating a solution to your problem. Here's an outline of it:
Inside
v-for
blocks we have full access to parent scope properties.v-for
also supports an optional second argument for the index of the current item.
– https://v2.vuejs.org/v2/guide/list.html#Basic-Usage
The v-for
directive has a second argument giving you the index of the item.
v-for="(item, index) in items"
Since you want the active
class on the first item you can use an expression testing if the index
is 0
and bind it to the class attribute.
:class="{ 'active': index === 0 }"