How to remove quotes from around a string in Golang

Use a slice expression:

s = s[1 : len(s)-1]

If there's a possibility that the quotes are not present, then use this:

if len(s) > 0 && s[0] == '"' {
    s = s[1:]
}
if len(s) > 0 && s[len(s)-1] == '"' {
    s = s[:len(s)-1]
}

playground example

Use slice expressions. You should write robust code that provides correct output for imperfect input. For example,

package main

import "fmt"

func trimQuotes(s string) string {
    if len(s) >= 2 {
        if s[0] == '"' && s[len(s)-1] == '"' {
            return s[1 : len(s)-1]
        }
    }
    return s
}

func main() {
    tests := []string{
        `"hello""world"`,
        `"""hello"""`,
        `"`,
        `""`,
        `"""`,
        `goodbye"`,
        `"goodbye"`,
        `goodbye"`,
        `good"bye`,
    }

    for _, test := range tests {
        fmt.Printf("`%s` -> `%s`\n", test, trimQuotes(test))
    }
}

Output:

`"hello""world"` -> `hello""world`
`"""hello"""` -> `""hello""`
`"` -> `"`
`""` -> ``
`"""` -> `"`
`goodbye"` -> `goodbye"`
`"goodbye"` -> `goodbye`
`goodbye"` -> `goodbye"`
`good"bye` -> `good"bye`

strings.Trim() can be used to remove the leading and trailing whitespace from a string. It won't work if the double quotes are in between the string.

// strings.Trim() will remove all the occurrences from the left and right

s := `"""hello"""`
fmt.Println("Before Trim: " + s)                    // Before Trim: """hello"""
fmt.Println("After Trim: " + strings.Trim(s, "\"")) // After Trim: hello

// strings.Trim() will not remove any occurrences from inside the actual string

s2 := `""Hello" " " "World""`
fmt.Println("\nBefore Trim: " + s2)                  // Before Trim: ""Hello" " " "World""
fmt.Println("After Trim: " + strings.Trim(s2, "\"")) // After Trim: Hello" " " "World

Playground link - https://go.dev/play/p/yLdrWH-1jCE