How to remove trailing whitespaces with sed?

Thanks to codaddict for suggesting the -i option.

The following command solves the problem on Snow Leopard

sed -i '' -e's/[ \t]*$//' "$1"

At least on Mountain Lion, Viktor's answer will also remove the character 't' when it is at the end of a line. The following fixes that issue:

sed -i '' -e's/[[:space:]]*$//' "$1"

It is best to also quote $1:

sed -i.bak 's/[[:blank:]]*$//' "$1"

You can use the in place option -i of sed for Linux and Unix:

sed -i 's/[ \t]*$//' "$1"

Be aware the expression will delete trailing t's on OSX (you can use gsed to avoid this problem). It may delete them on BSD too.

If you don't have gsed, here is the correct (but hard-to-read) sed syntax on OSX:

sed -i '' -E 's/[ '$'\t'']+$//' "$1"

Three single-quoted strings ultimately become concatenated into a single argument/expression. There is no concatenation operator in bash, you just place strings one after the other with no space in between.

The $'\t' resolves as a literal tab-character in bash (using ANSI-C quoting), so the tab is correctly concatenated into the expression.