How to show the first N elements of a block and hide the others in css?
Also, like Giovanni's solution, something like this could also work.
.container > .row:nth-child(3) ~ .row {
/* this rule targets the rows after the 3rd .row */
display: none;
}
You don't even need CSS3 selectors:
.row + .row + .row + .row {
display: none;
}
This should work even in IE7.
Updated fiddle
You have a
.notarow
as the first child, so you have to account for that in your:nth-child()
formula. Because of that.notarow
, your first.row
becomes the second child overall of the parent, so you have to count starting from the second to the fourth:.row:nth-child(-n+4) { display: block; }
Updated fiddle
.row { display: none; } .row:nth-child(-n+4) { display: block; }
<div class="content"> <div class="notarow">I'm not a row and I must remain visible</div> <div class="row">Row 1</div> <div class="row">Row 2</div> <div class="row">Row 3</div> <div class="row">Row 4</div> <div class="row">Row 5</div> <div class="row">Row 6</div> </div>
What you're doing is fine.