how to substract two datetime.time values in django template,and how to format a duration as hour,minutes
You've got a problem. You can't -- and shouldn't be able to -- compare two times. Is 11pm before or after 1am? It depends whether or not they're on the same day.
You need to either store them as datetime
or something else that represents a relatively absolute time, or you need to turn them into datetime
s like this:
def todatetime(time):
return datetime.datetime.today().replace(hour=time.hour, minute=time.minute, second=time.second,
microsecond=time.microsecond, tzinfo=time.tzinfo)
def timestodelta(starttime, endtime):
return todatetime(endtime) - todatetime(starttime)
This will fail to give the expected answer if the two calls to today
span midnight.
Then you should probably use this app for a DurationField which stores a timedelta
to store the result in the database for easy display.
I don't see where is the problem, apart in case the end-time would be later than 24 hours after the start-time.
Suppose that start-time is 9:00:00 and end-time is 13:00:00
If these times were taken on August 15, 9:00:00 and August 17, 13:00:00 , there would be no sense to try to obtain the time delta between them without knowing the days 15 and 17.
Hence there are two cases:
either the start time and end time may be really separated by more than 24 hours , then as it has already been said, you must move to the use of datetime's objects
either there is always less than 24 hours between the start-time and the end-time, then the problem is simple.
==========================
Let us examine the second case.
If
start-time 11:30:00
end-time.. 12:35:00
The end is evidently 1 hour 5 minutes after the start
If
start-time 11:30:00
end-time.. 10:35:00
The end can't be before the start in the same morning, then the end is in fact in the morning of the next day after the day in which is the start, that is to say 24 hours later.
The same reasoning applies when the start is in the afternoon and the end time is apparently before the start time in the same day, in afternoon or morning: end time is in fact in the the next day, morning or afternoon, it depends but it's still 24 hours later.
1)
So a little function, that need only the attributes of the times is sufficient to deduct the time difference:
def difft(start,end):
a,b,c,d = start.hour, start.minute, start.second, start.microsecond
w,x,y,z = end.hour, end.minute, end.second, end.microsecond
delt = (w-a)*60 + (x-b) + (y-c)/60. + (z-d)/60000000
return delt + 1440 if delt<0 else delt
The following code is only for a better display of the result:
from datetime import time
def difft(start,end):
a,b,c,d = start.hour, start.minute, start.second, start.microsecond
w,x,y,z = end.hour, end.minute, end.second, end.microsecond
delt = (w-a)*60 + (x-b) + (y-c)/60. + (z-d)/60000000
D = '%sh %smn %ss %sms - %sh %smn %ss %sms == '
ft = '%s + 1440 = %s (1440 = 24x60mn)'
return D % (w,x,y,z,a,b,c,d) +( ft % (delt, delt+1440) if delt<0 else str(delt))
print difft(time(11,30,0),time(12,35,0))
print difft(time(11,30,0),time(10,35,0))
print
print difft(time(20,40,0),time(22,41,0))
print difft(time(20,40,0),time(18,41,0))
result
12h 35mn 0s 0ms - 11h 30mn 0s 0ms == 65.0
10h 35mn 0s 0ms - 11h 30mn 0s 0ms == -55.0 + 1440 = 1385.0 (1440 = 24x60mn)
22h 41mn 0s 0ms - 20h 40mn 0s 0ms == 121.0
18h 41mn 0s 0ms - 20h 40mn 0s 0ms == -119.0 + 1440 = 1321.0 (1440 = 24x60mn)
2)
To obtain the durations in a more readable format:
def difft2(start,end):
a,b,c,d = start.hour, start.minute, start.second, start.microsecond
w,x,y,z = end.hour, end.minute, end.second, end.microsecond
delt = (w-a)*60 + (x-b) + (y-c)/60. + (z-d)/60000000.
if delt < 0:
delt += 1440
hh,rem = divmod(delt,60)
hh = int(hh)
mm = int(rem)
rem = (rem - mm)*60
ss = int(rem)
ms = (rem - ss)*1000000
ms = int(ms)
SS = '%sh %smn %ss %sms - %sh %smn %ss %sms == %sh %smn %ss %sms'
return SS % (w,x,y,z,a,b,c,d,hh,mm,ss,ms)
print difft2(time(11,30,0),time(12,35,45,478129))
print difft2(time(11,30,45,11),time(10,35,45,12))
print
print difft2(time(20,40,0),time(22,41,0))
print difft2(time(20,40,0),time(18,41,0))
result
12h 35mn 45s 478129ms - 11h 30mn 0s 0ms == 1h 5mn 45s 478128ms
10h 35mn 45s 12ms - 11h 30mn 45s 11ms == 23h 5mn 0s 1ms
22h 41mn 0s 0ms - 20h 40mn 0s 0ms == 2h 1mn 0s 0ms
18h 41mn 0s 0ms - 20h 40mn 0s 0ms == 22h 1mn 0s 0ms
You can use builtin timedelta template tag. In django template answer would be:
{{ t2|timeuntil:t1 }}