inherit from two classes in C#

Multitiple inheritance is not possible in C#, however it can be simulated using interfaces, see Simulated Multiple Inheritance Pattern for C#.

The basic idea is to define an interface for the members on class B that you wish to access (call it IB), and then have C inherit from A and implement IB by internally storing an instance of B, for example:

class C : A, IB
{
    private B _b = new B();

    // IB members
    public void SomeMethod()
    {
        _b.SomeMethod();
    }
}

There are also a couple of other alternaitve patterns explained on that page.

An common alternative to inheritance is delegation (also called composition): X "has a" Y rather than X "is a" Y. So if A has functionality for dealing with Foos, and B has functionality for dealing with Bars, and you want both in C, then something like this:

public class A() {
  private FooManager fooManager = new FooManager(); // (or inject, if you have IoC)

  public void handleFoo(Foo foo) {
    fooManager.handleFoo(foo);
  }
}

public class B() {
  private BarManager barManager = new BarManager(); // (or inject, if you have IoC)

  public void handleBar(Bar bar) {
    barManager.handleBar(bar);
  }
}

public class C() {
  private FooManager fooManager = new FooManager(); // (or inject, if you have IoC)
  private BarManager barManager = new BarManager(); // (or inject, if you have IoC)

  ... etc
}

If you want to literally use the method code from A and B you can make your C class contain an instance of each. If you code against interfaces for A and B then your clients don't need to know you're giving them a C rather than an A or a B.

interface IA { void SomeMethodOnA(); }
interface IB { void SomeMethodOnB(); }
class A : IA { void SomeMethodOnA() { /* do something */ } }
class B : IB { void SomeMethodOnB() { /* do something */ } }
class C : IA, IB
{
    private IA a = new A();
    private IB b = new B();
    void SomeMethodOnA() { a.SomeMethodOnA(); }
    void SomeMethodOnB() { b.SomeMethodOnB(); }
}