Initializing 2D array in Python
Using list comprehensions, you can say:
arr = [[None for x in range(6)] for y in range(6)]
Then you will have arr[1][2] = 10
working as expected. This is not a very normal thing to do, however. What are you going to use the nested lists for? There may be a better way. For example, working with arrays is made much easier with the numpy package.
@Cameron is correct in suggesting that you use NumPy to deal with arrays of numerical data. And for the second part of your question, ~Niklas B. is spot on with his suggestion to use defaultdict
.
What hasn't been covered is why [[None]*6]*6
behaves strangely.
The answer is that [None]*6
creates a list with six None
s in it (like you expect), but [list]*6
does not make six independent copies of list
- it makes six copies of a reference to the same list
.
Idiomatic Python has a section that may explain this better: "Other languages have variables - Python has names".