Is there a generic way for a function to reference itself?
http://docs.python.org/library/inspect.html looks promising:
import inspect
def foo():
felf = globals()[inspect.getframeinfo(inspect.currentframe()).function]
print felf.__name__, felf.__doc__
you can also use the sys
module to get the name of the current function:
import sys
def bar():
felf = globals()[sys._getframe().f_code.co_name]
print felf.__name__, felf.__doc__
There is no generic way for a function to refer to itself. Consider using a decorator instead. If all you want as you indicated was to print information about the function that can be done easily with a decorator:
from functools import wraps
def showinfo(f):
@wraps(f)
def wrapper(*args, **kwds):
print(f.__name__, f.__hash__)
return f(*args, **kwds)
return wrapper
@showinfo
def aa():
pass
If you really do need to reference the function, then just add it to the function arguments:
def withself(f):
@wraps(f)
def wrapper(*args, **kwds):
return f(f, *args, **kwds)
return wrapper
@withself
def aa(self):
print(self.__name__)
# etc.
Edit to add alternate decorator:
You can also write a simpler (and probably faster) decorator that will make the wrapped function work correctly with Python's introspection:
def bind(f):
"""Decorate function `f` to pass a reference to the function
as the first argument"""
return f.__get__(f, type(f))
@bind
def foo(self, x):
"This is a bound function!"
print(self, x)
>>> foo(42)
<function foo at 0x02A46030> 42
>>> help(foo)
Help on method foo in module __main__:
foo(self, x) method of builtins.function instance
This is a bound function!
This leverages Python's descriptor protocol: functions have a __get__
method that is used to create bound methods. The decorator simply uses the existing method to make the function a bound method of itself. It will only work for standalone functions, if you wanted a method to be able to reference itself you would have to do something more like the original solution.