Is there a "goto" statement in bash?

No, there is not; see §3.2.4 "Compound Commands" in the Bash Reference Manual for information about the control structures that do exist. In particular, note the mention of break and continue, which aren't as flexible as goto, but are more flexible in Bash than in some languages, and may help you achieve what you want. (Whatever it is that you want . . .)

If you are using it to skip part of a large script for debugging (see Karl Nicoll's comment), then if false could be a good option (not sure if "false" is always available, for me it is in /bin/false):

# ... Code I want to run here ...

if false; then

# ... Code I want to skip here ...

fi

# ... I want to resume here ...

The difficulty comes in when it's time to rip out your debugging code. The "if false" construct is pretty straightforward and memorable, but how do you find the matching fi? If your editor allows you to block indent, you could indent the skipped block (then you'll want to put it back when you're done). Or a comment on the fi line, but it would have to be something you'll remember, which I suspect will be very programmer-dependent.

It indeed may be useful for some debug or demonstration needs.

I found that Bob Copeland solution http://bobcopeland.com/blog/2012/10/goto-in-bash/ elegant:

#!/bin/bash
# include this boilerplate
function jumpto
{
    label=$1
    cmd=$(sed -n "/$label:/{:a;n;p;ba};" $0 | grep -v ':$')
    eval "$cmd"
    exit
}

start=${1:-"start"}

jumpto $start

start:
# your script goes here...
x=100
jumpto foo

mid:
x=101
echo "This is not printed!"

foo:
x=${x:-10}
echo x is $x

results in:

$ ./test.sh
x is 100
$ ./test.sh foo
x is 10
$ ./test.sh mid
This is not printed!
x is 101