Is there a `valueof` similar to `keyof` in TypeScript?
There is another way to extract the union type of the object:
const myObj = { a: 1, b: 'some_string' } as const;
type values = typeof myObj[keyof typeof myObj];
Result: 1 | "some_string"
If anyone still looks for implementation of valueof
for any purposes, this is a one I came up with:
type valueof<T> = T[keyof T]
Usage:
type actions = {
a: {
type: 'Reset'
data: number
}
b: {
type: 'Apply'
data: string
}
}
type actionValues = valueof<actions>
Works as expected :) Returns an Union of all possible types
UPDATE: Looks like the question title attracts people looking for a union of all possible property value types, analogous to the way keyof
gives you the union of all possible property key types. Let's help those people first. You can make a ValueOf
analogous to keyof
, by using indexed access types with keyof T
as the key, like so:
type ValueOf<T> = T[keyof T];
which gives you
type Foo = { a: string, b: number };
type ValueOfFoo = ValueOf<Foo>; // string | number
For the question as stated, you can use individual keys, narrower than keyof T
, to extract just the value type you care about:
type sameAsString = Foo['a']; // look up a in Foo
type sameAsNumber = Foo['b']; // look up b in Foo
In order to make sure that the key/value pair "match up" properly in a function, you should use generics as well as indexed access types, like this:
declare function onChange<K extends keyof JWT>(key: K, value: JWT[K]): void;
onChange('id', 'def456'); // okay
onChange('expire', new Date(2018, 3, 14)); // okay
onChange('expire', 1337); // error. 1337 not assignable to Date
The idea is that the key
parameter allows the compiler to infer the generic K
parameter. Then it requires that value
matches JWT[K]
, the indexed access type you need.