itoa function problem

www.cplusplus.com says:

This function is not defined in ANSI-C and is not part of C++, but is supported by some compilers.

Therefore, I'd strongly suggest that you don't use it. However, you can achieve this quite straightforwardly using stringstream as follows:

stringstream ss;
ss << myInt;
string myString = ss.str();

Boost way:

string str = boost::lexical_cast<string>(n);

itoa() is not part of any standard so you shouldn't use it. There's better ways, i.e...

C:

int main() {
    char n_str[10];
    int n = 25;

    sprintf(n_str, "%d", n);

    return 0;
}

C++:

using namespace std;
int main() {
    ostringstream n_str;
    int n = 25;

    n_str << n;

    return 0;
}

itoa depends on compiler, so better use the following methods :-

method 1 :If you are using c++11, just go for std::to_string. It will do the trick.

method 2 :sprintf works for both c & c++. ex- ex - to_string

#include <bits/stdc++.h>
using namespace std;
int main ()
{
  int i;
  char buffer [100];
  printf ("Enter a number: ");
  scanf ("%d",&i);

  string str = to_string(i);
  strcpy(buffer, str.c_str());

  cout << buffer << endl;
  return 0;
}

Note - compile using -std=c++0x.

C++ sprintf:

int main ()
{
int i;
  char buffer [100];
  printf ("Enter a number: ");
  scanf ("%d",&i);
  sprintf(buffer, "%d", i);
  return 0;
}`