Javascript DateDiff
Okay for those who would like a working example here is a simple DateDiff ex that tells date diff by day in a negative value (date passed already) or positive (date is coming).
EDIT: I updated this script so it will do the leg work for you and convert the results in to in this case a -10 which means the date has passed. Input your own dates for currDate and iniPastedDate and you should be good to go!!
//Set the two dates
var currentTime = new Date()
var currDate = currentTime.getMonth() + 1 + "/" + currentTime.getDate() + "/" + currentTime.getFullYear() //Todays Date - implement your own date here.
var iniPastedDate = "8/7/2012" //PassedDate - Implement your own date here.
//currDate = 8/17/12 and iniPastedDate = 8/7/12
function DateDiff(date1, date2) {
var datediff = date1.getTime() - date2.getTime(); //store the getTime diff - or +
return (datediff / (24*60*60*1000)); //Convert values to -/+ days and return value
}
//Write out the returning value should be using this example equal -10 which means
//it has passed by ten days. If its positive the date is coming +10.
document.write (DateDiff(new Date(iniPastedDate),new Date(currDate))); //Print the results...
Your first try does addition first and then subtraction. You cannot subtract strings anyway, so that yields NaN
.
The second trry has no closing )
. Apart from that, you're calling getTime
on strings. You'd need to use new Date(...).getTime()
. Note that you get the result in milliseconds when subtracting dates. You could format that by taking out full days/hours/etc.
function setDateWeek(setDay){
var d = new Date();
d.setDate(d.getDate() - setDay); // <-- add this
var curr_date = d.getDate();
var curr_month = d.getMonth() + 1;
var curr_year = d.getFullYear();
return curr_date + "-" + curr_month + "-" + curr_year;
}
setDateWeek(1);