Launch application from another using a deeplink
The above answer can only open the app with screen defined as LAUNCHER, not with deep link.
This will work to link app XYZ with any app:
private void startAppXYZfromThisFuckinApp() {
// pass the uri (scheme & screen path) of a screen defined from app XXX that you want to open (e.g HomeActivity)
Uri uri = Uri.parse("xyz://screen/home");
Intent mapIntent = new Intent(Intent.ACTION_VIEW, uri);
//Verify if app XYZ has this screen path
PackageManager packageManager = getPackageManager();
List<ResolveInfo> activities =
packageManager.queryIntentActivities(mapIntent, 0);
boolean isIntentSafe = activities.size() > 0;
//Start HomeActivity of app XYZ because it's existed
if (isIntentSafe) {
startActivity(mapIntent);
}
}
And obviously, in app XYZ AndroidManifest.xml must be something like this:
<activity
android:name=".HomeActivity"
<intent-filter>
<action android:name="android.intent.action.VIEW"/>
<category android:name="android.intent.category.DEFAULT"/>
<category android:name="android.intent.category.BROWSABLE"/>
<data>
android:host="screen/home"
android:scheme="xyz" />
</intent-filter>
It will now open screen HomeActivity from app XYZ!
Try to create the Intent from PackageManager and set the action (ACTION_VIEW) and the data (myAction) before launching deepLink:
Uri myAction = Uri.parse(mEditText.getText().toString());
PackageManager packageManager = getPackageManager();
Intent intent = packageManager.getLaunchIntentForPackage(<app_destination_package>);
if (intent != null) {
intent.setAction(Intent.ACTION_VIEW);
intent.setData(myAction);
startActivity(intent);
}
Change your manifest like this
<data
android:host="open"
android:pathPattern="/myAction?param=123"
android:scheme=" myApp" />
To send an intent in the first activity
Intent intent = new Intent (Intent.ActionView);
intent.setData (Uri.Parse (DEEP_LINK_URL));
And in your second activity
if(getIntent()!=null){
Intent deepLink = getIntent();
deepLink.getScheme();
deepLink.getData().getPath();
}