Limits of integration on double integrals
Note that $x=y^4$ and $x=1$ intersect at $ (x,y)=(1,\pm1)$. which define the limits for the integration region in the $xy$- plane. Thus, the volume integral is
$$\int_{-1}^1 \int_{y^4}^1 (4-2y)dxdy =\frac{32}5$$