Loading environment modules within a python script

One of our admins was able to solve the problem for me using os.popen() calls to modulecmd:

cmd = os.popen('/path/to/modulecmd python load my-module')
exec(cmd)

While the accepted solution works, I found it to be easier to write:

import sys
sys.path.insert(0, '/path/to/environment/modules')
# Environment modules become available by loading python.py (the name choice could be better here)
from python import module

# ...
module('use', '/some/dir')
module('load', 'program/1.2.3')

This looks more pythonic to me and also it allows IDEs to offer auto-completion etc.

I know this question's kind of old but it's still relevant enough that I was looking for the answer, so I'm posting what I found that works as well:

At least in the 3.2.9+ sources, you can include the python "init" file to get a python function version of module:

>>> exec(open('/usr/local/Modules/default/init/python.py').read())
>>> module('list')
No Modulefiles Currently Loaded.
>>> module('load','foo')
>>> module('list')
Currently Loaded Modulefiles:
  1) foo/1.0

I've been told earlier versions can do the same without the .py extension, but that's second hand, so ymmv.

Alternative "init" file location (from comment by @lib): /usr/share/Modules/init/python.py

To use with Python 3, version 4.0 or later of Environment Modules is required, as that is the first version to have a bug-free Python3-compliant version of the Python init file.