Loop through all elements in XML using NodeList

    DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
    DocumentBuilder db = dbf.newDocumentBuilder();
    Document dom = db.parse("file.xml");
    Element docEle = dom.getDocumentElement();
    NodeList nl = docEle.getChildNodes();
    int length = nl.getLength();
    for (int i = 0; i < length; i++) {
        if (nl.item(i).getNodeType() == Node.ELEMENT_NODE) {
            Element el = (Element) nl.item(i);
            if (el.getNodeName().contains("staff")) {
                String name = el.getElementsByTagName("name").item(0).getTextContent();
                String phone = el.getElementsByTagName("phone").item(0).getTextContent();
                String email = el.getElementsByTagName("email").item(0).getTextContent();
                String area = el.getElementsByTagName("area").item(0).getTextContent();
                String city = el.getElementsByTagName("city").item(0).getTextContent();
            }
        }
    }

Iterate over all children and nl.item(i).getNodeType() == Node.ELEMENT_NODE is used to filter text nodes out. If there is nothing else in XML what remains are staff nodes.

For each node under stuff (name, phone, email, area, city)

 el.getElementsByTagName("name").item(0).getTextContent(); 

el.getElementsByTagName("name") will extract the "name" nodes under stuff, .item(0) will get you the first node and .getTextContent() will get the text content inside.

Edit: Since we have jackson I would do this in a different way. Define a pojo for the object:

public class Staff {
    private String name;
    private String phone;
    private String email;
    private String area;
    private String city;
...getters setters
}

Then using jackson:

    JsonNode root = new XmlMapper().readTree(xml.getBytes());
    ObjectMapper mapper = new ObjectMapper();
    root.forEach(node -> consume(node, mapper));



private void consume(JsonNode node, ObjectMapper mapper) {
    try {
        Staff staff = mapper.treeToValue(node, Staff.class);
        //TODO your job with staff
    } catch (JsonProcessingException e) {
        e.printStackTrace();
    }
}

Here is another way to loop through XML elements using JDOM.

        List<Element> nodeNodes = inputNode.getChildren();
        if (nodeNodes != null) {
            for (Element nodeNode : nodeNodes) {
                List<Element> elements = nodeNode.getChildren(elementName);
                if (elements != null) {
                    elements.size();
                    nodeNodes.removeAll(elements);
                }
            }

public class XMLParser {
   public static void main(String[] args){
      try {
         DocumentBuilder dBuilder = DocumentBuilderFactory.newInstance().newDocumentBuilder();
         Document doc = dBuilder.parse(new File("xml input"));
         NodeList nl=doc.getDocumentElement().getChildNodes();

         for(int k=0;k<nl.getLength();k++){
             printTags((Node)nl.item(k));
         }
      } catch (Exception e) {/*err handling*/}
   }

   public static void printTags(Node nodes){
       if(nodes.hasChildNodes()  || nodes.getNodeType()!=3){
           System.out.println(nodes.getNodeName()+" : "+nodes.getTextContent());
           NodeList nl=nodes.getChildNodes();
           for(int j=0;j<nl.getLength();j++)printTags(nl.item(j));
       }
   }
}

Recursively loop through and print out all the xml child tags in the document, in case you don't have to change the code to handle dynamic changes in xml, provided it's a well formed xml.

Tags:

Java

Xml

Parsing