making a big summation sign
You can use the command \mathlarger
of the relsize
package. It increases the size and it can be nested. For example:
\documentclass{article}
\usepackage{amsmath}
\usepackage{relsize}
\begin{document}
\begin{equation}
\cos x = \mathlarger{\mathlarger{\sum}}_{n=0}^{\infty}\frac{(ix)^2n}{(2n)!}
\end{equation}
\end{document}
.....
Well, there's always a graphicx
solution.
\nsum[<optional>]
The command \nsum
resizes the \sum
symbol by the factor 1.4
(fits OP's fraction). It does take an optional argument to give another factor.
I admit that the \raisebox
factor calculation is a bit sketchy as it uses the text style \sum
symbol for the calculation but for cmr
it's a good fit and I'm too lazy to take a closer look at the needed dimension calculation.
\resum{<arg>}
Another more dynamic approach would be to take the dimensions of the \sum
's terms and resize the \sum
sign so that it fits their vertical dimensions. To only specify the therms once the \resum
also defines (overwrites) \s
so that one can use
\resum{<what to sum>}_{foo}^{bar} \s
(I also tried to use \resizebox
that takes the dimension instead of a factor, but I couldn't quite work out how to use \resizebox
and \resizebox*
.)
The second screenshot (produced by the lua-visual-debug
package shows why \resum
is in my eyes unstable and shouldn't be used. (But I don't think that a bigger \sum
sign is even needed, anyway)
Code
\documentclass{article}
\usepackage{amsmath}
%\usepackage{lua-visual-debug} requires LuaTeX (used only for demonstration purposes)
\usepackage{graphicx}
\usepackage{calc}
\newlength{\depthofsumsign}
\setlength{\depthofsumsign}{\depthof{$\sum$}}
\newlength{\totalheightofsumsign}
\newlength{\heightanddepthofargument}
\newcommand{\nsum}[1][1.4]{% only for \displaystyle
\mathop{%
\raisebox
{-#1\depthofsumsign+1\depthofsumsign}
{\scalebox
{#1}
{$\displaystyle\sum$}%
}
}
}
\newcommand{\resum}[1]{%
\def\s{#1}
\mathop{
\mathpalette\resumaux{#1}
}
}
\newcommand{\resumaux}[2]{% internally
\sbox0{$#1#2$}
\sbox1{$#1\sum$}
\setlength{\heightanddepthofargument}{\wd0+\dp0}
\setlength{\totalheightofsumsign}{\wd1+\dp1}
\def\quot{\DivideLengths{\heightanddepthofargument}{\totalheightofsumsign}}
\nsum[\quot]%
}
% http://tex.stackexchange.com/a/6424/16595
\makeatletter
\newcommand*{\DivideLengths}[2]{%
\strip@pt\dimexpr\number\numexpr\number\dimexpr#1\relax*65536/\number\dimexpr#2\relax\relax sp\relax
}
\makeatother
\begin{document}
\begin{equation}
\cos x = \nsum_{n=0}^\infty \frac{(ix)^2n}{(2n)!}
\end{equation}
\begin{equation}
\rlap{\rule[.57ex]{.55\linewidth}{.1pt}}\rlap{\rule{.55\linewidth}{.1pt}}
\sum_{n=1}^\infty \nsum_{1.4} \nsum[2]_2 \nsum[2.5]_{2.5} \nsum[3]_{n=1}^\infty \nsum[3]_{\displaystyle n=1}^{\displaystyle \infty}
\end{equation}
\begin{equation}
\cos x = \resum{\frac{(ix)^2n}{(2n)!}}_{n=0}^\infty \s \quad \resum{\frac{1}{2}}_{n=0}^\infty\s \quad \resum{\frac{\strut 1}{\strut 2}}_{n=0}^\infty\s
\end{equation}
\end{document}
Output
A closer look at how \resum
does (not) work
If you're willing to use the Mathtime Professional II font package, you could use its \xl\sum
, \XL\sum
, \XXL\sum
etc commands to get larger summation symbols.
\documentclass{article}
\usepackage{newtxtext}
\usepackage[lite]{mtpro2}
\begin{document}
The summation symbols below are generated by \texttt{\string\sum} as well as by \texttt{\string\xl\string\sum}, \texttt{\string\XL\string\sum}, and \texttt{\string\XXL\string\sum} of the \texttt{mtpro2} package. (There is also \texttt{\string\XXXL\string\sum}, but it's not shown here.)
\[
\sum_{i=1}^N \frac{1}{2^{-i}} \qquad
\xl\sum_{i=1}^N \frac{1}{2^{-i}} \qquad
\XL\sum_{i=1}^N \frac{1}{2^{-i}} \qquad
\XXL\sum_{i=1}^N \frac{1}{2^{-i}}
\]
\end{document}
Two additional comments. (i) The mtpro2
font package isn't free of charge, although it's not exactly expensive either; actually, all that's needed to produce the large summation symbols is the lite
subset of the package, which is free of charge. (ii) The mtpro2
math font package uses a "Times Roman" font style; this may or may not be to your liking.