mysql check if numbers are in a comma separated list

Not the most pretty solution, but it works:

select
   UID
from
   YOUR_TABLE
where
   find_in_set('3', cast(NUMBERS as char)) > 0
   and
   find_in_set('15', cast(NUMBERS as char)) > 0

Note that it's string comparison, so you may need to cast your input parameters to char as well.

You Can Try As Like Following :

 SELECT * FROM table_name WHERE FIND_IN_SET('3', NUMBERS) AND  FIND_IN_SET('15', NUMBERS)

Also check if this is helpful to anyone

An Extended function to eliminate the limitation of native FIND_IN_SET() in MySQL, this new extended version FIND_IN_SET_X() provides feature to compare one list with another list.

i.e.

mysql> SELECT FIND_IN_SET_X('x,c','a,b,c,d'); -> 3 

Checkout this link for more details.

This one also works:

SELECT * FROM table WHERE 3 IN (NUMBERS) AND 15 IN (NUMBERS)

using the IN will look into a comma separated string eg. these two

WHERE banana IN ('apple', 'banana', 'coconut')
WHERE 3 IN (2,3,6,8,90)

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