MySQL delete duplicate records but keep latest

DELETE 
FROM
  `tbl_job_title` 
WHERE id NOT IN 
  (SELECT 
    * 
  FROM
    (SELECT 
      MAX(id) 
    FROM
      `tbl_job_title` 
    GROUP BY NAME) tbl)

revised and working version!!! thank you @Gaurav

Try this method

DELETE t1 FROM test t1, test t2 
WHERE t1.id > t2.id AND t1.email = t2.email

Correct way is

DELETE FROM `tablename`
  WHERE `id` NOT IN (
    SELECT * FROM (
      SELECT MAX(`id`) FROM `tablename`
        GROUP BY `name`
    ) 
  )

Imagine your table test contains the following data:

  select id, email
    from test;

ID                     EMAIL                
---------------------- -------------------- 
1                      aaa                  
2                      bbb                  
3                      ccc                  
4                      bbb                  
5                      ddd                  
6                      eee                  
7                      aaa                  
8                      aaa                  
9                      eee 

So, we need to find all repeated emails and delete all of them, but the latest id.
In this case, aaa, bbb and eee are repeated, so we want to delete IDs 1, 7, 2 and 6.

To accomplish this, first we need to find all the repeated emails:

      select email 
        from test
       group by email
      having count(*) > 1;

EMAIL                
-------------------- 
aaa                  
bbb                  
eee  

Then, from this dataset, we need to find the latest id for each one of these repeated emails:

  select max(id) as lastId, email
    from test
   where email in (
              select email 
                from test
               group by email
              having count(*) > 1
       )
   group by email;

LASTID                 EMAIL                
---------------------- -------------------- 
8                      aaa                  
4                      bbb                  
9                      eee                                 

Finally we can now delete all of these emails with an Id smaller than LASTID. So the solution is:

delete test
  from test
 inner join (
  select max(id) as lastId, email
    from test
   where email in (
              select email 
                from test
               group by email
              having count(*) > 1
       )
   group by email
) duplic on duplic.email = test.email
 where test.id < duplic.lastId;

I don't have mySql installed on this machine right now, but should work

Update

The above delete works, but I found a more optimized version:

 delete test
   from test
  inner join (
     select max(id) as lastId, email
       from test
      group by email
     having count(*) > 1) duplic on duplic.email = test.email
  where test.id < duplic.lastId;

You can see that it deletes the oldest duplicates, i.e. 1, 7, 2, 6:

select * from test;
+----+-------+
| id | email |
+----+-------+
|  3 | ccc   |
|  4 | bbb   |
|  5 | ddd   |
|  8 | aaa   |
|  9 | eee   |
+----+-------+

Another version, is the delete provived by Rene Limon

delete from test
 where id not in (
    select max(id)
      from test
     group by email)