MySQL Select By Newest Timestamp
If someone has a similar problem in SQL Server, this will work for you (the suggested MySQL query in the previous post doesn't work in SQL Server):
SELECT * FROM my_table
WHERE timestamp = ( SELECT MAX( timestamp ) FROM my_table
WHERE user_2 = 22 )
SELECT * FROM my_table -- standard stuff
WHERE user_2 = 22 -- predicate
ORDER BY timestamp DESC -- this means highest number (most recent) first
LIMIT 1; -- just want the first row
Edit:
By the way, in case you're curious why your original query didn't work, let's break down the pieces:
- select some stuff from
my_table
... - where
user_2
= 22 - and
timestamp
= (some value, let's put it aside for now) - limit 1
Now, coming back to that timestamp
value, it comes from your subquery:
SELECT MAX( timestamp ) FROM my_table
Note that this subquery doesn't restrict any rows based on user_2
-- it asks for what's the max timestamp in the whole table. That max timestamp is the first one in your table above: (user_1 = 23, user_2 = 25, timestamp = 2012-08-10 22:00:00).
So, let's plug that back to the top-level query:
- select some stuff from
my_table
... - where user_2 = 22
- and timestamp = 2012-08-10 22:00:00
- limit 1
... and you can see there isn't such a row.
Another method is to GROUP BY
the user_2
column as you calculate MAX(timestamp)
. Doing so will make MAX(timestamp)
calculate not the latest date in the entire table, but rather the latest timestamp for each group of records with the same user_2
value.
So, for example, your query could be:
SELECT * FROM my_table
WHERE user_2 = 22
AND timestamp =
(SELECT MAX(timestamp) FROM my_table
WHERE user_2 = 22
GROUP BY user_2)
LIMIT 1;
This query is adapted from the answer I found in this excellent answer.