Non-AJAX jQuery POST request

$("#see_comments").click(function () {
    $('<form action="comments.php" method="POST"/>')
        .append($('<input type="hidden" name="aid">').val(imgnum))
        .appendTo($(document.body)) //it has to be added somewhere into the <body>
        .submit();
});

I know what you are trying to do, but its not what you want.

First, unless you are changing data on the server, don't use a POST request. Just have #see_comments be a normal <a href='/comments.php?aid=1'>...

If you have to use POST, then do this to get the page to follow your call:

$("#see_comments").click(function() {
  $('<form action="comments.php" method="POST">' + 
    '<input type="hidden" name="aid" value="' + imgnum + '">' +
    '</form>').submit();
});

How this would actually work.

First $.post is only an AJAX method and cannot be used to do a traditional form submit like you are describing. So, to be able to post a value and navigate to the new page, we need to simulate a form post.

So the flow is as follows:

  1. You click on the image, and your JS code gets the imgnum
  2. Next, someone clicks on #see_comments
  3. We create a temporary form with the imgnum value in it as a hidden field
  4. We submit that form, which posts the value and loads the comments.php page
  5. Your comments.php page will have access to the posted variable (i.e. in PHP it would be $_POST['aid'])

Tags:

Javascript

Jquery

Recent Posts