oracle SQL how to remove time from date

You can use TRUNC on DateTime to remove Time part of the DateTime. So your where clause can be:

AND TRUNC(p1.PA_VALUE) >= TO_DATE('25/10/2012', 'DD/MM/YYYY')

The TRUNCATE (datetime) function returns date with the time portion of the day truncated to the unit specified by the format model.

When you convert your string to a date you need to match the date mask to the format in the string. This includes a time element, which you need to remove with truncation:

select 
    p1.PA_VALUE as StartDate,
    p2.PA_VALUE as EndDate
from WP_Work p 
LEFT JOIN PARAMETER p1 on p1.WP_ID=p.WP_ID AND p1.NAME = 'StartDate'
LEFT JOIN PARAMETER p2 on p2.WP_ID=p.WP_ID AND p2.NAME = 'Date_To'
WHERE p.TYPE = 'EventManagement2'
AND trunc(TO_DATE(p1.PA_VALUE, 'DD-MM-YYYY HH24:MI')) >= TO_DATE('25/10/2012', 'DD/MM/YYYY')
AND trunc(TO_DATE(p2.PA_VALUE, 'DD-MM-YYYY HH24:MI')) <= TO_DATE('26/10/2012', 'DD/MM/YYYY')

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Outside the scope of the question, but storing dates as strings is bad practice, and storing date times is even worse.

1. We need to convert the strings to dates in order to do any form of date processing (arithmetic, interval assessment, etc) on them
2. Strings offer no guarantees regarding format, so we run the risk of date corruption crashing our code. We can defend against this by employing VALIDATE_CONVERSION() (available since 12c, find out more ) but it's still a PITN
3. Using non-standard datatypes makes it harder to reason about the data model and the code we build over it.

We can use TRUNC function in Oracle DB. Here is an example.

SELECT TRUNC(TO_DATE('01 Jan 2018 08:00:00','DD-MON-YYYY HH24:MI:SS')) FROM DUAL

Output: 1/1/2018