Pass a list to a function to act as multiple arguments

Yes, you can use the *args (splat) syntax:

function_that_needs_strings(*my_list)

where my_list can be any iterable; Python will loop over the given object and use each element as a separate argument to the function.

See the call expression documentation.

There is a keyword-parameter equivalent as well, using two stars:

kwargs = {'foo': 'bar', 'spam': 'ham'}
f(**kwargs)

and there is equivalent syntax for specifying catch-all arguments in a function signature:

def func(*args, **kw):
    # args now holds positional arguments, kw keyword arguments

Since Python 3.5 you can unpack unlimited amount of lists.

PEP 448 - Additional Unpacking Generalizations

So this will work:

a = ['1', '2', '3', '4']
b = ['5', '6']
function_that_needs_strings(*a, *b)

function_that_needs_strings(*my_list) # works!

You can read all about it here.

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