Pointer to Array of Pointers

The correct answer is:

int* arr[MAX];
int* (*pArr)[MAX] = &arr;

Or just:

        int* arr  [MAX];
typedef int* arr_t[MAX];

arr_t* pArr = &arr;

The last part reads as "pArr is a pointer to array of MAX elements of type pointer to int".

In C the size of array is stored in the type, not in the value. If you want this pointer to correctly handle pointer arithmetic on the arrays (in case you'd want to make a 2-D array out of those and use this pointer to iterate over it), you - often unfortunately - need to have the array size embedded in the pointer type.

Luckily, since C99 and VLAs (maybe even earlier than C99?) MAX can be specified in run-time, not compile time.

Should just be:

int* array[SIZE];
int** val = array;  

There's no need to use an address-of operator on array since arrays decay into implicit pointers on the right-hand side of the assignment operator.