Problems with a PHP shell script: "Could not open input file"

Have you tried:

#!/usr/local/bin/php

I.e. without the -q part? That's what the error message "Could not open input file: -q" means. The first argument to php if it doesn't look like an option is the name of the PHP file to execute, and -q is CGI only.

EDIT: A couple of (non-related) tips:

1. You don't need to terminate the last block of PHP with ?>. In fact, it is often better not to.
2. When executed on the command line, PHP defines the global constant STDIN to fopen("php://stdin", "r"). You can use that instead of opening "php://stdin" a second time: $fd = STDIN;

I just experienced this issue and it was because I was trying to run a script from the wrong directory.. doh! It happens to the best of us.