Property getters and setters

Setters and Getters apply to computed properties; such properties do not have storage in the instance - the value from the getter is meant to be computed from other instance properties. In your case, there is no x to be assigned.

Explicitly: "How can I do this without explicit backing ivars". You can't - you'll need something to backup the computed property. Try this:

class Point {
  private var _x: Int = 0             // _x -> backingX
  var x: Int {
    set { _x = 2 * newValue }
    get { return _x / 2 }
  }
}

Specifically, in the Swift REPL:

 15> var pt = Point()
pt: Point = {
  _x = 0
}
 16> pt.x = 10
 17> pt
$R3: Point = {
  _x = 20
}
 18> pt.x
$R4: Int = 10

Setters/getters in Swift are quite different than ObjC. The property becomes a computed property which means it does not have a backing variable such as _x as it would in ObjC.

In the solution code below you can see the xTimesTwo does not store anything, but simply computes the result from x.

See Official docs on computed properties.

The functionality you want might also be Property Observers.

What you need is:

var x: Int

var xTimesTwo: Int {
    set {
       x = newValue / 2
    }
    get {
        return x * 2
    }
}

You can modify other properties within the setter/getters, which is what they are meant for.

You can customize the set value using property observer. To do this use 'didSet' instead of 'set'.

class Point {

var x: Int {
    didSet {
        x = x * 2
    }
}
...

As for getter ...

class Point {

var doubleX: Int {
    get {
        return x / 2
    }
}
...