Python convert decimal to hex
What about this:
hex(dec).split('x')[-1]
Example:
>>> d = 30
>>> hex(d).split('x')[-1]
'1e'
~Rich
By using -1 in the result of split(), this would work even if split returned a list of 1 element.
If you want to code this yourself instead of using the built-in function hex()
, you can simply do the recursive call before you print the current digit:
def ChangeHex(n):
if (n < 0):
print(0)
elif (n<=1):
print n,
else:
ChangeHex( n / 16 )
x =(n%16)
if (x < 10):
print(x),
if (x == 10):
print("A"),
if (x == 11):
print("B"),
if (x == 12):
print("C"),
if (x == 13):
print("D"),
if (x == 14):
print("E"),
if (x == 15):
print ("F"),
This isn't exactly what you asked for but you can use the "hex" function in python:
>>> hex(15)
'0xf'