Python elegant inverse function of int(string,base)
Maybe this shouldn't be an answer, but it could be helpful for some: the built-in format
function does convert numbers to string in a few bases:
>>> format(255, 'b') # base 2
'11111111'
>>> format(255, 'd') # base 10
'255'
>>> format(255, 'o') # base 8
'377'
>>> format(255, 'x') # base 16
'ff'
If you use Numpy, there is numpy.base_repr
.
You can read the code under numpy/core/numeric.py
. Short and elegant
This thread has some example implementations.
Actually I think your solution looks rather nice, it's even recursive which is somehow pleasing here.
I'd still simplify it to remove the else
, but that's probably a personal style thing. I think if foo: return
is very clear, and doesn't need an else
after it to make it clear it's a separate branch.
def digit_to_char(digit):
if digit < 10:
return str(digit)
return chr(ord('a') + digit - 10)
def str_base(number,base):
if number < 0:
return '-' + str_base(-number, base)
(d, m) = divmod(number, base)
if d > 0:
return str_base(d, base) + digit_to_char(m)
return digit_to_char(m)
I simplified the 0-9 case in digit_to_char()
, I think str()
is clearer than the chr(ord())
construct. To maximize the symmetry with the >= 10
case an ord()
could be factored out, but I didn't bother since it would add a line and brevity felt better. :)