Regular expression to return text between parenthesis

If your problem is really just this simple, you don't need regex:

s[s.find("(")+1:s.find(")")]

Use re.search(r'\((.*?)\)',s).group(1):

>>> import re
>>> s = u'abcde(date=\'2/xc2/xb2\',time=\'/case/test.png\')'
>>> re.search(r'\((.*?)\)',s).group(1)
u"date='2/xc2/xb2',time='/case/test.png'"