Rotating right an array of int in c#?

You can use the beauty of the Linq langage to return an IEnumerable without dealing with array size:

/// <summary>
/// Get c = a mod (b) with c in [0, b[ like the mathematical definition
/// </summary>
public static int MathMod(int a, int b)
{
    int c = ((a % b) + b) % b;
    return c;
}
public static IEnumerable<T> ShiftRight<T>(IList<T> values, int shift)
{
    for (int index = 0; index < values.Count; index++)
    {
        yield return values[MathMod(index - shift, values.Count)];
    }
}

Usage :

[TestMethod]
public void TestMethod1()
{
    var res = ShiftRight(new [] { 1, 2, 3, 4, 5, 6 }, 2).ToArray();
    Assert.IsTrue(res.SequenceEqual(new[] { 5, 6, 1, 2, 3, 4 }));
}