Scala add new column to dataframe by expression
In Spark 2.x, you can create a new column C5 with expression "C2/C3+C4" using withColumn()
and org.apache.spark.sql.functions._
,
val currentDf = Seq(
("steak", 1, 1, 150),
("steak", 2, 2, 180),
("fish", 3, 3, 100)
).toDF("C1", "C2", "C3", "C4")
val requiredDf = currentDf
.withColumn("C5", (col("C2")/col("C3")+col("C4")))
Also, you can do the same using org.apache.spark.sql.Column
as well.
(But the space complexity is bit higher in this approach than using org.apache.spark.sql.functions._
due to the Column object creation)
val requiredDf = currentDf
.withColumn("C5", (new Column("C2")/new Column("C3")+new Column("C4")))
This worked perfectly for me. I am using Spark 2.0.2.
Two approaches:
import spark.implicits._ //so that you could use .toDF
val df = Seq(
("steak", 1, 1, 150),
("steak", 2, 2, 180),
("fish", 3, 3, 100)
).toDF("C1", "C2", "C3", "C4")
import org.apache.spark.sql.functions._
// 1st approach using expr
df.withColumn("C5", expr("C2/(C3 + C4)")).show()
// 2nd approach using selectExpr
df.selectExpr("*", "(C2/(C3 + C4)) as C5").show()
+-----+---+---+---+--------------------+
| C1| C2| C3| C4| C5|
+-----+---+---+---+--------------------+
|steak| 1| 1|150|0.006622516556291391|
|steak| 2| 2|180| 0.01098901098901099|
| fish| 3| 3|100| 0.02912621359223301|
+-----+---+---+---+--------------------+
This can be done using expr
to create a Column
from an expression:
val df = Seq((1,2)).toDF("x","y")
val myExpression = "x+y"
import org.apache.spark.sql.functions.expr
df.withColumn("z",expr(myExpression)).show()
+---+---+---+
| x| y| z|
+---+---+---+
| 1| 2| 3|
+---+---+---+