Shell Script - Make directory if it doesn't exist
if [ -L $dirname]
Look at the error message produced by this line: “[: missing `]'” or some such (depending on which shell you're using). You need a space inside the brackets. You also need double quotes around the variable expansion unless you use double brackets; you can either learn the rules, or use a simple rule: always use double quotes around variable substitution and command substitution — "$foo"
, "$(foo)"
.
if [ -L "$dirname" ]
Then there's a logic error: you're creating the directory only if there is a symbolic link which does not point to a directory. You presumably meant to have a negation in there.
Don't forget that the directory might be created while your script is running, so it's possible that your check will show that the directory doesn't exist but the directory will exist when you try to create it. Never do “check then do”, always do “do and catch failure”.
The right way to create a directory if it doesn't exist is
mkdir -p -- "$dirname"
(The double quotes in case $dirname
contains whitespace or globbing characters, the --
in case it starts with -
.)
Try this code:
echo "Enter directory name"
read dirname
if [ ! -d "$dirname" ]
then
echo "File doesn't exist. Creating now"
mkdir ./$dirname
echo "File created"
else
echo "File exists"
fi
Output Log:
Chitta:~/cpp/shell$ ls
dir.sh
Chitta:~/cpp/shell$ sh dir.sh
Enter directory name
New1
File doesn't exist. Creating now
File created
chitta:~/cpp/shell$ ls
New1 dir.sh
Chitta:~/cpp/shell$ sh dir.sh
Enter directory name
New1
File exists
Chitta:~/cpp/shell$ sh dir.sh
Enter directory name
New2
File doesn't exist. Creating now
File created
Chitta:~/cpp/shell$ ls
New1 New2 dir.sh
read -p "Enter Directory Name: " dirname
if [[ ! -d "$dirname" ]]
then
if [[ ! -L $dirname ]]
then
echo "Directory doesn't exist. Creating now"
mkdir $dirname
echo "Directory created"
else
echo "Directory exists"
fi
fi