Skip first result from v-for vuejs2

use v-for + v-if (see guide)

When they exist on the same node, v-for has a higher priority than v-if. That means the v-if will be run on each iteration of the loop separately. This can be useful when you want to render nodes for only some items, like below:

UPDATED: Added a better approach

example:

new Vue({
  el: '#app',
  computed: {
    filteredArray() {
      return this.array.filter(item => !!item.firstName);
    },
  },
  data: {
    array: [
    {
      firstName: '',
      lastName: '',
      age: 0
    },
    {
      firstName: 'Dirk',
      lastName: 'Doe',
      age: 41
    },
    {
      firstName: 'Julia',
      lastName: 'Doe',
      age: 25
    }
    ]
  }
})

<script src="https://unpkg.com/[email protected]/dist/vue.js"></script>
<div id="app">
  <li v-for="user in filteredArray">
      {{ user.firstName }} - age: {{user.age}}
  </li>
  <pre>old array = {{ array }}</pre>
</div>

What Voldymyr wrote

<li v-for="(value, index) in array" v-if="value.firstName">
      {{ value.firstName }} - index: {{index}}
</li>

seems fine to exclude data which has got firstname null or empty. But to avoid the first record (that's what you asked), the best way I can think of is,

<li v-for="(value, index) in array" v-if="index">
  {{ value.firstName }} - index: {{index}}
<li>

The index will be 0 for the first record, and v-if(index) will be false.

Change

this.arrayresults = [{id:'' ,username: '',useremail: '',userphone:'',}] 

to

this.arrayresults = []