Sort a list from another list IDs

docs = docs.OrderBy(d => docsIds.IndexOf(d.Id)).ToList();

Jodrell's answer is best, but actually he reimplemented System.Linq.Enumerable.Join. Join also uses Lookup and keeps ordering of source.

    docIds.Join(
      docs,
      i => i,
      d => d.Id,
      (i, d) => d);

Since you don't specify T,

IEnumerable<T> OrderBySequence<T, TId>(
       this IEnumerable<T> source,
       IEnumerable<TId> order,
       Func<T, TId> idSelector)
{
    var lookup = source.ToDictionary(idSelector, t => t);
    foreach (var id in order)
    {
        yield return lookup[id];
    }
}

Is a generic extension for what you want.

You could use the extension like this perhaps,

var orderDocs = docs.OrderBySequence(docIds, doc => doc.Id);

---

A safer version might be

IEnumerable<T> OrderBySequence<T, TId>(
       this IEnumerable<T> source,
       IEnumerable<TId> order,
       Func<T, TId> idSelector)
{
    var lookup = source.ToLookup(idSelector, t => t);
    foreach (var id in order)
    {
        foreach (var t in lookup[id])
        {
           yield return t;
        }
    }
}

which will work if source does not zip exactly with order.