SQL Server check resultant data type of expression
All that I can think of are the ISNUMERIC and ISDATE functions.
These will return a 1/0 when passed an expression. I can't think of anything that will return the type if given an expression unfortunately.
UPDATE:
Try SQL_VARIANT_PROPERTY! I think this is what you are looking for. Hard to track down...
SQL_VARIANT_PROPERTY is close
DECLARE @what sql_variant;
DECLARE @foo decimal(19,3) = 1, @bar decimal(11,7) = 2;
SELECT @what = @foo / @bar;
SELECT
SQL_VARIANT_PROPERTY(@what, 'BaseType'),
SQL_VARIANT_PROPERTY(@what, 'Precision'),
SQL_VARIANT_PROPERTY(@what, 'Scale'),
SQL_VARIANT_PROPERTY(@what, 'MaxLength');
SELECT @what = @foo + @bar;
SELECT
SQL_VARIANT_PROPERTY(@what, 'BaseType'),
SQL_VARIANT_PROPERTY(@what, 'Precision'),
SQL_VARIANT_PROPERTY(@what, 'Scale'),
SQL_VARIANT_PROPERTY(@what, 'MaxLength');
SELECT @what = @foo * @bar;
SELECT
SQL_VARIANT_PROPERTY(@what, 'BaseType'),
SQL_VARIANT_PROPERTY(@what, 'Precision'),
SQL_VARIANT_PROPERTY(@what, 'Scale'),
SQL_VARIANT_PROPERTY(@what, 'MaxLength');
Or temp table/SELECT..INTO.. as an extension of what you've already done
Edit: Remus' answer?
I've never seen such a function.
From the MSDN article on T-SQL expressions:
For a simple expression made up of a single constant, variable, scalar function, or column name: the data type, collation, precision, scale, and value of the expression is the data type, collation, precision, scale, and value of the referenced element.
When two expressions are combined by using comparison or logical operators, the resulting data type is Boolean and the value is one of the following: TRUE, FALSE, or UNKNOWN. For more information about Boolean data types, see Comparison Operators (Transact-SQL).
When two expressions are combined by using arithmetic, bitwise, or string operators, the operator determines the resulting data type.
Complex expressions made up of many symbols and operators evaluate to a single-valued result. The data type, collation, precision, and value of the resulting expression is determined by combining the component expressions, two at a time, until a final result is reached. The sequence in which the expressions are combined is defined by the precedence of the operators in the expression.