std::cin input with spaces?
It doesn't "fail"; it just stops reading. It sees a lexical token as a "string".
Use std::getline
:
int main()
{
std::string name, title;
std::cout << "Enter your name: ";
std::getline(std::cin, name);
std::cout << "Enter your favourite movie: ";
std::getline(std::cin, title);
std::cout << name << "'s favourite movie is " << title;
}
Note that this is not the same as std::istream::getline
, which works with C-style char
buffers rather than std::string
s.
Update
Your edited question bears little resemblance to the original.
You were trying to getline
into an int
, not a string or character buffer. The formatting operations of streams only work with operator<<
and operator>>
. Either use one of them (and tweak accordingly for multi-word input), or use getline
and lexically convert to int
after-the-fact.
You have to use cin.getline()
:
char input[100];
cin.getline(input,sizeof(input));
The Standard Library provides an input function called ws
, which consumes whitespace from an input stream. You can use it like this:
std::string s;
std::getline(std::cin >> std::ws, s);