String-Date conversion with nanoseconds
private String convertDate(String cdate)
{
SimpleDateFormat dateFormat = new SimpleDateFormat("dd.MM.yyyy HH:mm:ss:SSSSSSS");
SimpleDateFormat postFormater = new SimpleDateFormat("yyyy-MM-dd");
Date convertedDate;
try
{
convertedDate = dateFormat.parse(cdate);
cdate = postFormater.format(convertedDate);
}
catch (ParseException e)
{
Toast.makeText(getApplicationContext(),e.toString(),Toast.LENGTH_SHORT).show();
}
return cdate;
}
Try this.
To drop the nanoseconds, use:
new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.")
The result you are getting is absolutely right.
Let's analyze this:
17.08.2012 05:35:19:7600000
- 17: Day of month (17th)
- 08: Month of year (August)
- 2012: Year (2012)
- 05: Hour of day (5am)
- 35: Minute of hour (:35)
- 19: Second of minute (:19)
- 7600000: Milliseconds of second (7,600,000)
Now, the way the VM sees this is that you are declaring the time of day as 5:35:19am, then adding 7,600,000 milliseconds to it. 7,600,000 milliseconds = 7,600 seconds = 2 hours, 6 minutes, 40 seconds. 5:35:19am + 02:06:40 = 7:41:59am (and 0 milliseconds). This is the result you are getting. (It also appears that you are not setting the timezone properly, so the GMT string is 3 hours behind your result.)
If you want to retain the :7600000
, to my knowledge this is not possible. As this can be simplified into seconds, the VM will automatically reduce it into the other time increments. The milliseconds (the SSSS
) should be for storing values <1000.
I'd suggest you create a new SimpleDateFormat
for your output; but remember that the milliseconds will be absorbed into the other times (since they are all stored as a single long
in the Date
object).
This is what you need (but it will loose millisecond information):
"dd.MM.yyyy HH:mm:ss.'000000'"
If you used "dd.MM.yyyy HH:mm:ss.SSSSSS"
, then would get three leading zeros for your milliseconds.
If you used "dd.MM.yyyy HH:mm:ss.SSS'000'"
, then you could format a date, but not parse any date.
Try it out:
public static void main(String[] args) throws ParseException {
printDate("dd.MM.yyyy HH:mm:ss.SSS");//02.05.2010 21:45:58.073
printDate("dd.MM.yyyy HH:mm:ss.SSSSSS");//02.05.2010 21:45:58.000073
printDate("dd.MM.yyyy HH:mm:ss.SSS'000'");//02.05.2010 21:45:58.073000
printDate("dd.MM.yyyy HH:mm:ss.'000000'");//02.05.2010 21:45:58.000000
tryToParseDate("dd.MM.yyyy HH:mm:ss.SSS");//good
tryToParseDate("dd.MM.yyyy HH:mm:ss.SSSSSS");//good
tryToParseDate("dd.MM.yyyy HH:mm:ss.SSS'000'");//bad
tryToParseDate("dd.MM.yyyy HH:mm:ss.'000000'");//good
}
private static void printDate(String formatString) {
Date now = new Date();
SimpleDateFormat format = new SimpleDateFormat(formatString);
String formattedDate = format.format(now);
// print that date
System.out.println(formattedDate);
}
private static void tryToParseDate(String formatString) {
Date now = new Date();
SimpleDateFormat format = new SimpleDateFormat(formatString);
String formattedDate = format.format(now);
// try to parse it again
try {
format.parse(formattedDate);
System.out.println("good");
} catch (ParseException e) {
System.out.println("bad");
}
}