Translate a Glypho program

Pyth, 37 35 34 bytes

The code contains unprintable characters, so here is the xxd hexdump:

0000000: 5663 7a34 7040 2e22 216f d78c 40bf d4f0  Vcz4p@."!o..@...
0000010: 38d6 7dfe 7312 3ff8 ea22 6958 4e7b 4e55  8.}.s.?.."iXN{NU
0000020: 5433                                     T3

Here's a printable version at 36 bytes:

Vcz4p@"ni >\\1   <d+[o*e-!]"iXN{NUT3

Try it online. Test suite.

Explanation

Vcz4p@."…"iXN{NUT3       implicit: z = input
  z                      input
 c 4                     split to 4-character blocks
V                        loop over that in N
           X               replace...
            N                in current part
             {N              unique chars in current part, in order
               UT            with numbers 0-9
          i      3         interpret as base 3
     @                     take that item of
      ."…"                   string "ni >\\1   <d+[o*e-!]"
    p                      and print without newline

CJam, 42 39 35 bytes

Saved 4 bytes borrowing user81655's idea of using base 3 instead of base 4.

l4/{__&f#3b"ni >\1   <d+[o*e-!]"=}%

Run all test cases.

There's gotta be a better way to compress the lookup table of commands...

JavaScript (ES6), 97

For each block of 4 characters, I substitute each symbol with its position in the block, getting a base 4 number. For instance 'aabc' -> '0023'. The possibile numbers are in the range 0..0123, that is 0..27 in decimal. I use the number as an index to find the right instruction character from a 28 chars string.

s=>s.replace(/.{4}/g,s=>'n..i....>.\\1....<d.+[o.*e-!]'[[...s].map(c=>n=n*4+s.indexOf(c),n=0),n])

Test

F=s=>s.replace(/.{4}/g,s=>'n..i....>.\\1....<d.+[o.*e-!]'[[...s].map(c=>n=n*4+s.indexOf(c),n=0),n])

function test() { O.textContent=F(I.value) }

test();

#I { width:90% }

<input id=I value="nananananananana batman!" oninput="test()">
<br><span id=O></span>