Using awk to remove the Byte-order mark

Using GNU sed (on Linux or Cygwin):

# Removing BOM from all text files in current directory:
sed -i '1 s/^\xef\xbb\xbf//' *.txt

On FreeBSD:

sed -i .bak '1 s/^\xef\xbb\xbf//' *.txt

Advantage of using GNU or FreeBSD sed: the -i parameter means "in place", and will update files without the need for redirections or weird tricks.

On Mac:

This awk solution in another answer works, but the sed command above does not work. At least on Mac (Sierra) sed documentation does not mention supporting hexadecimal escaping ala \xef.

A similar trick can be achieved with any program by piping to the sponge tool from moreutils:

awk '…' INFILE | sponge INFILE

Try this:

awk 'NR==1{sub(/^\xef\xbb\xbf/,"")}{print}' INFILE > OUTFILE

On the first record (line), remove the BOM characters. Print every record.

Or slightly shorter, using the knowledge that the default action in awk is to print the record:

awk 'NR==1{sub(/^\xef\xbb\xbf/,"")}1' INFILE > OUTFILE

1 is the shortest condition that always evaluates to true, so each record is printed.

Enjoy!

-- ADDENDUM --

Unicode Byte Order Mark (BOM) FAQ includes the following table listing the exact BOM bytes for each encoding:

Bytes         |  Encoding Form
--------------------------------------
00 00 FE FF   |  UTF-32, big-endian
FF FE 00 00   |  UTF-32, little-endian
FE FF         |  UTF-16, big-endian
FF FE         |  UTF-16, little-endian
EF BB BF      |  UTF-8

Thus, you can see how \xef\xbb\xbf corresponds to EF BB BF UTF-8 BOM bytes from the above table.

Not awk, but simpler:

tail -c +4 UTF8 > UTF8.nobom

To check for BOM:

hd -n 3 UTF8

If BOM is present you'll see: 00000000 ef bb bf ...