Using preg_replace on an array
preg_replace
doesn't modify in place. To permanently modify $array
, you simply need to assign the result of preg_replace
to it:
$array = preg_replace("/\d{1,2}IPT\.\w/", "IPT", $array);
works for me.
$array = array('00IPT.A', '0IPT.A');
$array = preg_replace("/\d{1,2}IPT\.\w/", "IPT", $array);
var_dump($array);
// output: array(2) { [0]=> string(3) "IPT" [1]=> string(3) "IPT" }
Note: the \d{1,2}
means one or two digits.
If you want to do this to a two-dimensional array, you need to loop through the first dimension:
$array = array( array('00IPT.A', 'notmatch'), array('neither', '0IPT.A') );
foreach ($array as &$row) {
$row = preg_replace("/\d{1,2}IPT\.\w/", "IPT", $row);
}
var_dump($array);
output:
array(2) {
[0]=> array(2) {
[0]=> string(3) "IPT"
[1]=> string(8) "notmatch"
}
[1]=> &array(2) {
[0]=> string(7) "neither"
[1]=> string(3) "IPT"
}
}
Note that you have to loop through each row by reference (&$row
) otherwise the original array will not be modified.