Using std::accumulate
You're wrong about accumulate operator taking two of the same type. It does that only if you want to. The use the operator is specifically sum = op(sum, *iter)
. Thus your code:
int count = std::accumulate(stuff.begin(), stuff.end(), 0, [](int current_sum, stuff_value_t const& value) { return current_sum + value.member; });
If you can't use lambda then of course you use the standard binders or boost::bind.
use functor:
class F { // sum Foos
F(int init = 0);
template<class T>
Foo operator()(const Foo &a, const T &b) const;
operator int() const;
};
int total_cost = std::accumulate(vec.begin(), vec.end(), F(0), F());
notice you can do other things as well:
class F { // sum foo values members
template<class T>
T operator()(const T &a, const Foo &b) const;
};
int total_cost = std::accumulate(vec.begin(), vec.end(), int(0), F());