VBA using ubound on a multidimensional array

You need to deal with the optional Rank parameter of UBound.

Dim arr(1 To 4, 1 To 3) As Variant
Debug.Print UBound(arr, 1)  '◄ returns 4
Debug.Print UBound(arr, 2)  '◄ returns 3

More at: UBound Function (Visual Basic)

[This is a late answer addressing the title of the question (since that is what people would encounter when searching) rather than the specifics of OP's question which has already been answered adequately]

Ubound is a bit fragile in that it provides no way to know how many dimensions an array has. You can use error trapping to determine the full layout of an array. The following returns a collection of arrays, one for each dimension. The count property can be used to determine the number of dimensions and their lower and upper bounds can be extracted as needed:

Function Bounds(A As Variant) As Collection
    Dim C As New Collection
    Dim v As Variant, i As Long

    On Error GoTo exit_function
    i = 1
    Do While True
        v = Array(LBound(A, i), UBound(A, i))
        C.Add v
        i = i + 1
    Loop
exit_function:
    Set Bounds = C
End Function

Used like this:

Sub test()
    Dim i As Long
    Dim A(1 To 10, 1 To 5, 4 To 10) As Integer
    Dim B(1 To 5) As Variant
    Dim C As Variant
    Dim sizes As Collection

    Set sizes = Bounds(A)
    Debug.Print "A has " & sizes.Count & " dimensions:"
    For i = 1 To sizes.Count
        Debug.Print sizes(i)(0) & " to " & sizes(i)(1)
    Next i

    Set sizes = Bounds(B)
    Debug.Print vbCrLf & "B has " & sizes.Count & " dimensions:"
    For i = 1 To sizes.Count
        Debug.Print sizes(i)(0) & " to " & sizes(i)(1)
    Next i

    Set sizes = Bounds(C)
    Debug.Print vbCrLf & "C has " & sizes.Count & " dimensions:"
    For i = 1 To sizes.Count
        Debug.Print sizes(i)(0) & " to " & sizes(i)(1)
    Next i
End Sub

Output:

A has 3 dimensions:
1 to 10
1 to 5
4 to 10

B has 1 dimensions:
1 to 5

C has 0 dimensions:

ubound(arr, 1) 

and

ubound(arr, 2)