Wait until all promises complete even if some rejected

Similar answer, but more idiomatic for ES6 perhaps:

const a = Promise.resolve(1);
const b = Promise.reject(new Error(2));
const c = Promise.resolve(3);

Promise.all([a, b, c].map(p => p.catch(e => e)))
  .then(results => console.log(results)) // 1,Error: 2,3
  .catch(e => console.log(e));


const console = { log: msg => div.innerHTML += msg + "<br>"};

<div id="div"></div>

Depending on the type(s) of values returned, errors can often be distinguished easily enough (e.g. use undefined for "don't care", typeof for plain non-object values, result.message, result.toString().startsWith("Error:") etc.)

Update, you probably want to use the built-in native Promise.allSettled:

Promise.allSettled([promise]).then(([result]) => {
   //reach here regardless
   // {status: "fulfilled", value: 33}
});

As a fun fact, this answer below was prior art in adding that method to the language :]

Sure, you just need a reflect:

const reflect = p => p.then(v => ({v, status: "fulfilled" }),
                            e => ({e, status: "rejected" }));

reflect(promise).then((v) => {
    console.log(v.status);
});

Or with ES5:

function reflect(promise){
    return promise.then(function(v){ return {v:v, status: "fulfilled" }},
                        function(e){ return {e:e, status: "rejected" }});
}


reflect(promise).then(function(v){
    console.log(v.status);
});

Or in your example:

var arr = [ fetch('index.html'), fetch('http://does-not-exist') ]

Promise.all(arr.map(reflect)).then(function(results){
    var success = results.filter(x => x.status === "fulfilled");
});