What is float in Java?
The thing is that decimal numbers defaults to double. And since double doesn't fit into float you have to tell explicitely you intentionally define a float. So go with:
float b = 3.6f;
In JAVA, values like:
- 8.5
- 3.9
- (and so on..)
Is assumed as double and not float.
You can also perform a cast in order to solve the problem:
float b = (float) 3.5
;
Another solution:
float b = 3.5f
;
Make it
float b= 3.6f;
A floating-point literal is of type float if it is suffixed with an ASCII letter F or f; otherwise its type is double and it can optionally be suffixed with an ASCII letter D or d
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In Java, when you type a decimal number as 3.6
, its interpreted as a double
. double
is a 64-bit precision IEEE 754 floating point, while float
is a 32-bit precision IEEE 754 floating point. As a float
is less precise than a double
, the conversion cannot be performed implicitly.
If you want to create a float, you should end your number with f
(i.e.: 3.6f
).
For more explanation, see the primitive data types definition of the Java tutorial.