What is the MS SQL Server capability similar to the MySQL FIELD() function?
I recommend a CTE (SQL server 2005+). No need to repeat the status codes or create the separate table.
WITH cte(status, RN) AS ( -- CTE to create ordered list and define where clause
SELECT 'active', 1
UNION SELECT 'approved', 2
UNION SELECT 'rejected', 3
UNION SELECT 'submitted', 4
)
SELECT <field1>, <field2>
FROM <table> tbl
INNER JOIN cte ON cte.status = tbl.status -- do the join
ORDER BY cte.RN -- use the ordering defined in the cte
Good luck,
Jason
For your particular example your could:
ORDER BY CHARINDEX(
',' + status + ',',
',rejected,active,submitted,approved,'
)
Note that FIELD
is supposed to return 0, 1, 2, 3, 4 where as the above will return 0, 1, 10, 17 and 27 so this trick is only useful inside the order by clause.
A set based approach would be to outer join with a table-valued-constructor:
LEFT JOIN (VALUES
('rejected', 1),
('active', 2),
('submitted', 3),
('approved', 4)
) AS lu(status, sort_order)
...
ORDER BY lu.sort_order
Use a CASE expression (SQL Server 2005+):
ORDER BY CASE status
WHEN 'active' THEN 1
WHEN 'approved' THEN 2
WHEN 'rejected' THEN 3
WHEN 'submitted' THEN 4
ELSE 5
END
You can use this syntax for more complex evaluation (including combinations, or if you need to use LIKE)
ORDER BY CASE
WHEN status LIKE 'active' THEN 1
WHEN status LIKE 'approved' THEN 2
WHEN status LIKE 'rejected' THEN 3
WHEN status LIKE 'submitted' THEN 4
ELSE 5
END