What is the python equivalent of JavaScript's Array.prototype.find?

Array.prototype.find() returns the first matching element in an array, given a predicate function, or undefined when there is no match.

Python has the filter() function, which filters an iterable on a predicate, and next(), which produces the first element of an iterable or an optional default. Combining these give you the equivalent:

next(filter(pred, iter), None)

where pred is a callable that returns True when an element matches the search criteria.

Demo:

>>> iterable = [42, 81, 117]
>>> parity_odd = lambda v: v % 2 == 1
>>> next(filter(parity_odd, iterable), None)
81
>>> iterable = [42, 2, 4]
>>> next(filter(parity_odd, iterable), None) is None
True

If you remove the second argument to next(), a StopIteration exception is raised when there is no matching element.

def find(pred, iterable):
  for element in iterable:
      if pred(element):
          return element
  return None

# usage:
find(lambda x: x.get("name") == "bbbb", obj.get("foo_list", []))