What's wrong with this truth table for implication?

Looks like whoever marked this assumed you knew which order the alphabet went in. Notice that if you put $p,q,r$ in alphabetical order you get

$$ \begin{array}{c|c|c|c} p & q & r & (\neg r \to p) \wedge (r \to q) \\\hline 0 & 0 & 0 & 0 \\\hline 0 & 0 & 1 & 0 \\\hline 0 & 1 & 0 & 0 \\\hline 0 & 1 & 1 & 1 \\\hline 1 & 0 & 0 & 1 \\\hline 1 & 0 & 1 & \color{red}0 \\\hline 1 & 1 & 0 & \color{red}1 \\\hline 1 & 1 & 1 & 1 \end{array} $$

They were probably marking like 30 of these truth tables so they only went off the final values and didn't pay attention to the order of the inputs.

Seems correct to me

\begin{array}{c:c}p & r & q & \neg r & (¬r \to p) & (r \to q) & (¬r \to p) \wedge (r \to q) \\ \hdashline 0 & 0 & 0 & 1 & 0 & 1 & 0 \\ \hdashline 0 & 0 & 1 & 1 & 0 & 1 & 0 \\ \hdashline 0 & 1 & 0 & 0 & 1 & 0 & 0 \\ \hdashline 0 & 1 & 1 & 0 & 1 & 1 & 1 \\ \hdashline 1 & 0 & 0 & 1 & 1 & 1 & 1 \\ \hdashline 1 & 0 & 1 & 1 & 1 & 1 & 1 \\ \hdashline 1 & 1 & 0 & 0 & 1 & 0 & 0 \\ \hdashline 1 & 1 & 1 & 0 & 1 & 1 & 1 \end{array}

Edit: Ah. Trevor has spotted what may have happened.