Why is argc not a constant?
The C standard (ISO/IEC 9899:2011) says:
5.1.2.2.1 Program startup
¶1 The function called at program startup is named
main
. The implementation declares no prototype for this function. It shall be defined with a return type of int and with no parameters:int main(void) { /* ... */ }
or with two parameters (referred to here as
argc
andargv
, though any names may be used, as they are local to the function in which they are declared):int main(int argc, char *argv[]) { /* ... */ }
or equivalent;10) or in some other implementation-defined manner.
¶2 If they are declared, the parameters to the
main
function shall obey the following constraints:
- The value of
argc
shall be nonnegative.argv[argc]
shall be a null pointer.- If the value of
argc
is greater than zero, the array membersargv[0]
throughargv[argc-1]
inclusive shall contain pointers to strings, which are given implementation-defined values by the host environment prior to program startup. The intent is to supply to the program information determined prior to program startup from elsewhere in the hosted environment. If the host environment is not capable of supplying strings with letters in both uppercase and lowercase, the implementation shall ensure that the strings are received in lowercase.- If the value of
argc
is greater than zero, the string pointed to byargv[0]
represents the program name;argv[0][0]
shall be the null character if the program name is not available from the host environment. If the value ofargc
is greater than one, the strings pointed to byargv[1]
throughargv[argc-1]
represent the program parameters.- The parameters
argc
andargv
and the strings pointed to by theargv
array shall be modifiable by the program, and retain their last-stored values between program startup and program termination.10) Thus,
int
can be replaced by a typedef name defined asint
, or the type ofargv
can be written aschar **argv
, and so on.
Note the last bullet point. It says that both argc
and argv
should be modifiable. They don't have to be modified, but they may be modified.
argc
is not normally a constant because the function signature for main()
pre-dates const
.
Since argc is a stack variable, changing it won't affect anything other than your own command line processing.
You are, of course, free to declare it const
if you want.
In this case, history is a factor. C defined these inputs as "not constant", and compatibility with (a good portion of) existing C code was an early goal of C++.
Some UNIX APIs, such as getopt
, actually do manipulate argv[]
, so it can't be made const
for that reason also.
(Aside: Interestingly, although getopt
's prototype suggests it won't modify argv[]
but may modify the strings pointed to, the Linux man page indicates that getopt
permutes its arguments, and it appears they know they're being naughty. The man page at the Open Group does not mention this permutation.)
Putting const
on argc
and argv
wouldn't buy much, and it would invalidate some old-school programming practices, such as:
// print out all the arguments:
while (--argc)
std::cout << *++argv << std::endl;
I've written such programs in C, and I know I'm not alone. I copied the example from somewhere.