wrongly asked question about precalculus?

It is not poorly formulated but may seem a bit tricky. This essentially is a piecewise function as

$f(x)=\frac{x}{x+3}: \quad x\in [0,5]$

$f(x)=-\frac{|x|}{|x|+3}: \quad x\in [-5,0)\quad\!\!$ because the function is odd.

Thus, $f(-3)=-\frac{1}{2}$ as you have mentioned.


You are indeed misinterpreting the question. The definition of $f$ as $f(x) = \frac{x}{x + 3}$ is (as explicitly stated) only defined on the interval $[0, 5],$ Further, it is given that $f$ is odd, which means indeed confirms that the domain is $[-5, 5],$ including at $x = -3.$

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Algebra Precalculus

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